Contents
IDENTIFICATION
Autar Kaw Section 002 Fall 2012 Due Date and Time: September 9, 2012
clc
clear all
Chapter 5 - Exercise X
A=[2 3 4 ; 5.2 6 7; 8 9 1]; disp('A matrix') disp(A) B=[4 6; 78 5;1 1]; disp('B matrix') disp(B) C=A*B; disp('A*B') disp(C)
A matrix 2.0000 3.0000 4.0000 5.2000 6.0000 7.0000 8.0000 9.0000 1.0000 B matrix 4 6 78 5 1 1 A*B 246.0000 31.0000 495.8000 68.2000 735.0000 94.0000
Chapter 6 - Exercise XX
syms t v=t^2+log(2*t); fprintf('Expression for velocity %s',char(v)) tt=5; v5=double(subs(v,t,tt)); fprintf('\nValue of velocity at t= %g is = %g',tt,v5)
Expression for velocity t^2+log(2*t) Value of velocity at t= 5 is = 27.3026